allow format_as() to format reference (#3739)
before this change, format_as() is unable to format a type which has `auto format_as() -> const another_type&`, and `another_type` is formattable. because `format_as_result` maps the result type as it is, and the compiler refuses to compile `static_cast<T*>(nullptr)`, where T is a reference type. but it would be handy if we could use `format_as()` to format types which, for instance, owns / inherit from a formattable type, and delegate the formatter to these variables instead without creating a copy of them. in this change: * instruct `format_as_result` to map the result type to the decayed type, so that `type` can be the decayed type of result type, and this also enables `type` to be formattable, as long as the decayed type is formattable. * corresponding test is added to format-test.cc Signed-off-by: Kefu Chai <tchaikov@gmail.com>
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@@ -1332,7 +1332,7 @@ using ulong_type = conditional_t<long_short, unsigned, unsigned long long>;
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template <typename T> struct format_as_result {
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template <typename U,
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FMT_ENABLE_IF(std::is_enum<U>::value || std::is_class<U>::value)>
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static auto map(U*) -> decltype(format_as(std::declval<U>()));
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static auto map(U*) -> remove_cvref_t<decltype(format_as(std::declval<U>()))>;
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static auto map(...) -> void;
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using type = decltype(map(static_cast<T*>(nullptr)));
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